a=4.965, b=2.343 तथा c=2.622 हो, तो a2-b3-c3-3abc का मान है
a=4.965,b=2.343,c=2.622 a+(−b)+(−c)=4.965−2.343−2.622=0 Therefore, a3+(−b)3+(−c)3=3×a×(−b)×(−c) ⟹a3−b3−c3−3abc = 0
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a=4.965,b=2.343,c=2.622 a+(−b)+(−c)=4.965−2.343−2.622=0 Therefore, a3+(−b)3+(−c)3=3×a×(−b)×(−c) ⟹a3−b3−c3−3abc = 0
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