If x=32 and x=−3 are roots of the quadratic equation ax2+7x+b=0, find the value of a and b.
If x=32,x=−3 are roots of the equation ax2+7x+b=0 then (x−32)(x−(−3))=0 ⇒(x−32)(x+3)=0 ⇒x2−32x+3x−2=0 ⇒x2+37x−2=0 ⇒3x²+7x−6=0 Compare the equation with ax²+7x+b=0 Therefore, a=3,b=−6
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